[Oct-2025] Pass The SecOps Group CNSP Exam in First Attempt Guaranteed!
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NEW QUESTION # 28
What will be the subnet mask for 192.168.0.1/18?
- A. 255.255.255.0
- B. 255.225.192.0
- C. 255.255.192.0
- D. 255.225.225.0
Answer: C
Explanation:
An IP address with a /18 prefix (CIDR notation) indicates 18 network bits in the subnet mask, leaving 14 host bits (32 total bits - 18). For IPv4 (e.g., 192.168.0.1):
Binary Mask: First 18 bits are 1s, rest 0s.
1st octet: 11111111 (255)
2nd octet: 11111111 (255)
3rd octet: 11000000 (192)
4th octet: 00000000 (0)
Decimal: 255.255.192.0
Calculation:
Bits: /18 = 2^14 hosts (16,384), minus 2 (network/broadcast) = 16,382 usable.
Range: 192.168.0.0-192.168.63.255 (3rd octet: 0-63, as 192 = 11000000 covers 6 bits).
Technical Details:
Subnet masks align on octet boundaries or mid-octet (e.g., 192 = 2^7 + 2^6).
Contrast: /24 = 255.255.255.0 (256 hosts), /16 = 255.255.0.0 (65,536 hosts).
Security Implications: Larger subnets (e.g., /18) increase broadcast domains, risking amplification attacks. CNSP likely teaches subnetting for segmentation (e.g., VLANs).
Why other options are incorrect:
A . 255.255.255.0: /24 (8 host bits), not /18.
B . 255.225.225.0: Invalid mask (225 = 11100001, non-contiguous 1s).
D . 255.225.192.0: Invalid (225 breaks binary sequence).
Real-World Context: Subnetting 192.168.0.0/18 isolates departments in enterprise networks.
NEW QUESTION # 29
What kind of files are "Dotfiles" in a Linux-based architecture?
- A. System files
- B. Driver files
- C. Hidden files
- D. Library files
Answer: C
Explanation:
In Linux, file visibility is determined by naming conventions, impacting how files are listed or accessed in the file system.
Why D is correct: "Dotfiles" are files or directories with names starting with a dot (e.g., .bashrc), making them hidden by default in directory listings (e.g., ls requires -a to show them). They are commonly used for user configuration, as per CNSP's Linux security overview.
Why other options are incorrect:
A: Library files (e.g., in /lib) aren't inherently hidden.
B: Driver files (e.g., kernel modules in /lib/modules) aren't dotfiles by convention.
C: System files may or may not be hidden; "dotfiles" specifically denotes hidden status.
NEW QUESTION # 30
Where are the password hashes stored in a Microsoft Windows 64-bit system?
- A. C:\Windows\System64\config\SAM
- B. C:\System64\config\SAM
- C. C:\Windows\config\System32\SAM
- D. C:\Windows\System32\config\SAM
Answer: D
Explanation:
Windows stores password hashes in the SAM (Security Account Manager) file, with a consistent location across 32-bit and 64-bit systems.
Why B is correct: The SAM file resides at C:\Windows\System32\config\SAM, locked during system operation for security. CNSP notes this for credential extraction risks.
Why other options are incorrect:
A: System64 does not exist; System32 is used even on 64-bit systems.
C: C:\System64 is invalid; the path starts with Windows.
D: config\System32 reverses the correct directory structure.
NEW QUESTION # 31
How would you establish a null session to a Windows host from a Windows command prompt?
- A. net use \hostname\c$ "" /u:NULL
- B. net use \hostname\ipc$ "" /u:NULL
- C. net use \hostname\ipc$ "" /u:""
- D. net use \hostname\c$ "" /u:""
Answer: C
Explanation:
A null session in Windows is an unauthenticated connection to certain administrative shares, historically used for system enumeration. The net use command connects to a share, and the IPC$ (Inter-Process Communication) share is the standard target for null sessions, allowing access without credentials when configured to permit it.
Why C is correct: The command net use \\hostname\ipc$ "" /u:"" specifies the IPC$ share and uses empty strings for the password (first "") and username (/u:""), establishing a null session. This syntax is correct for older Windows systems (e.g., XP or 2003) where null sessions were more permissive, a topic covered in CNSP for legacy system vulnerabilities.
Why other options are incorrect:
A: Targets the c$ share (not typically used for null sessions) and uses /u:NULL, which is invalid syntax; the username must be an empty string ("").
B: Targets c$ instead of ipc$, making it incorrect for null session establishment.
D: Uses ipc$ correctly but specifies /u:NULL, which is not the proper way to denote an empty username.
NEW QUESTION # 32
Which SMB (Server Message Block) network protocol versions are vulnerable to the EternalBlue (MS17-010) Windows exploit?
- A. SMBv2 only
- B. Both SMBv1 and SMBv2
- C. SMBv3 only
- D. SMBv1 only
Answer: D
Explanation:
EternalBlue (MS17-010) is an exploit targeting a buffer overflow in Microsoft's SMB (Server Message Block) implementation, leaked by the Shadow Brokers in 2017. SMB enables file/printer sharing:
SMBv1 (1980s): Legacy, used in Windows NT/XP.
SMBv2 (2006, Vista): Enhanced performance/security.
SMBv3 (2012, Windows 8): Adds encryption, multichannel.
Vulnerability:
EternalBlue exploits a flaw in SMBv1's SRVNET driver (srv.sys), allowing remote code execution via crafted packets. Microsoft patched it in March 2017 (MS17-010).
Affected OS: Windows XP to Server 2016 (pre-patch), if SMBv1 enabled.
Proof: WannaCry/NotPetya used it, targeting port 445/TCP.
SMBv1 Only: The bug resides in SMBv1's packet handling (e.g., TRANS2 requests). SMBv2/v3 rewrote this code, immune to the specific overflow.
Microsoft: Post-patch, SMBv1 is disabled by default (Windows 10 1709+).
Security Implications: CNSP likely stresses disabling SMBv1 (e.g., via Group Policy) and patching, as EternalBlue remains a threat in legacy environments.
Why other options are incorrect:
B, C: SMBv2/v3 aren't vulnerable; the flaw is SMBv1-specific.
D: SMBv2 isn't affected, only SMBv1.
Real-World Context: WannaCry's 2017 rampage hit unpatched SMBv1 systems (e.g., NHS), costing billions.
NEW QUESTION # 33
What ports can be queried to perform a DNS zone transfer?
- A. 53/TCP
- B. None of the above
- C. 53/UDP
- D. Both 1 and 2
Answer: A
Explanation:
A DNS zone transfer involves replicating the DNS zone data (e.g., all records for a domain) from a primary to a secondary DNS server, requiring a reliable transport mechanism.
Why A is correct: DNS zone transfers use TCP port 53 because TCP ensures reliable, ordered delivery of data, which is critical for transferring large zone files. CNSP notes that TCP is the standard protocol for zone transfers (e.g., AXFR requests), as specified in RFC 5936.
Why other options are incorrect:
B . 53/UDP: UDP port 53 is used for standard DNS queries and responses due to its speed and lower overhead, but it is not suitable for zone transfers, which require reliability over speed.
C . Both 1 and 2: This is incorrect because zone transfers are exclusively TCP-based, not UDP-based.
D . None of the above: Incorrect, as 53/TCP is the correct port for DNS zone transfers.
NEW QUESTION # 34
You are performing a security audit on a company's infrastructure and have discovered that the domain name system (DNS) server is vulnerable to a DNS cache poisoning attack. What is the primary security risk?
- A. The primary risk is that an attacker could manipulate the cache of the web server or proxy server to return incorrect content for a specific URL or web page.
- B. The primary risk is that an attacker could redirect traffic to a malicious website and steal sensitive information.
Answer: B
Explanation:
DNS cache poisoning, also known as DNS spoofing, involves an attacker injecting false DNS records into a resolver's cache, altering how domain names resolve.
Why A is correct: The primary risk is that an attacker can redirect users to malicious websites (e.g., phishing or malware sites) by poisoning the DNS cache with fake IP addresses. This can lead to credential theft, data exfiltration, or malware distribution. CNSP identifies this as the core threat of DNS cache poisoning, aligning with real-world attack vectors.
Why other option is incorrect:
B . Manipulate the cache of the web server or proxy server: This describes web cache poisoning, a different attack targeting HTTP caches, not DNS servers. DNS cache poisoning affects DNS resolution, not web or proxy server caches directly.
NEW QUESTION # 35
If a hash begins with $2a$, what hashing algorithm has been used?
- A. SHA512
- B. MD5
- C. SHA256
- D. Blowfish
Answer: D
Explanation:
The prefix $2a$ identifies the bcrypt hashing algorithm, which is based on the Blowfish symmetric encryption cipher (developed by Bruce Schneier). Bcrypt is purpose-built for password hashing, incorporating:
Salt: A random string (e.g., 22 Base64 characters) to thwart rainbow table attacks.
Work Factor: A cost parameter (e.g., $2a$10$ means 2^10 iterations), making it computationally expensive to brute-force.
Format: $2a$[cost]$[salt][hash]
Example: $2a$10$N9qo8uLOickgx2ZMRZoMyeIjZAgcfl7p92ldGxad68LJZdL17lhWy
$2a$: Bcrypt variant (original is $2$; $2a$ fixes a minor bug).
$10$: 1024 iterations.
Next 22 characters: Salt.
Remaining: Hashed password.
Used in /etc/shadow on Linux, bcrypt's adaptive nature ensures it remains secure as hardware improves. CNSP likely includes it in cryptography modules for its strength over older algorithms like MD5.
Why other options are incorrect:
B . SHA256: Part of the SHA-2 family, outputs a 64-character hexadecimal string (e.g., e3b0c442...), no $ prefix. It's faster, less suited for passwords.
C . MD5: Produces a 32-character hex string (e.g., d41d8cd9...), no prefix. It's cryptographically broken (collisions found).
D . SHA512: SHA-2 variant, 128-character hex (e.g., cf83e135...), no $ prefix, not salted by default.
Real-World Context: Bcrypt protects SSH keys and web app passwords (e.g., in PHP's password_hash()).
NEW QUESTION # 36
What RID is given to an Administrator account on a Microsoft Windows machine?
- A. 0
- B. 1
- C. 2
- D. 3
Answer: B
Explanation:
In Windows, security principals (users, groups) are identified by a Security Identifier (SID), formatted as S-1-<authority>-<domain>-<RID>. The RID (Relative Identifier) is the final component, unique within a domain or machine. For local accounts:
RID 500: Assigned to the built-in Administrator account on every Windows machine (e.g., S-1-5-21-<machine>-500).
Created during OS install, with full system privileges.
Disabled by default in newer Windows versions (e.g., 10/11) unless explicitly enabled.
RID 501: Guest account (e.g., S-1-5-21-<machine>-501), limited access.
Technical Details:
Stored in SAM (C:\Windows\System32\config\SAM).
Enumeration: Tools like wmic useraccount or net user reveal RIDs.
Domain Context: Domain Admins use RID 512, but the question specifies a local machine.
Security Implications: RID 500 is a prime target for brute-forcing or pass-the-hash attacks (e.g., Mimikatz). CNSP likely advises renaming/disabling it (e.g., via GPO).
Why other options are incorrect:
A . 0: Reserved (e.g., Null SID, S-1-0-0), not a user RID.
C . 501: Guest, not Administrator.
D . 100: Invalid; local user RIDs start at 1000 (e.g., custom accounts).
Real-World Context: Post-compromise, attackers query RID 500 (e.g., net user Administrator) for privilege escalation.
NEW QUESTION # 37
What types of attacks are phishing, spear phishing, vishing, scareware, and watering hole?
- A. Social engineering
- B. Ransomware
- C. Probes
- D. Insider threats
Answer: A
Explanation:
Social engineering exploits human psychology to manipulate individuals into divulging sensitive information, granting access, or performing actions that compromise security. Unlike technical exploits, it targets the "human factor," often bypassing technical defenses. The listed attacks fit this category:
Phishing: Mass, untargeted emails (e.g., fake bank alerts) trick users into entering credentials on spoofed sites. Uses tactics like urgency or trust (e.g., typosquatting domains).
Spear Phishing: Targeted phishing against specific individuals/organizations (e.g., CEO fraud), leveraging reconnaissance (e.g., LinkedIn data) for credibility.
Vishing (Voice Phishing): Phone-based attacks (e.g., fake tech support calls) extract info via verbal manipulation. Often spoofs caller ID.
Scareware: Fake alerts (e.g., "Your PC is infected!" pop-ups) scare users into installing malware or paying for bogus fixes. Exploits fear and urgency.
Watering Hole: Compromises trusted websites frequented by a target group (e.g., industry forums), infecting visitors via drive-by downloads. Relies on habitual trust.
Technical Details:
Delivery: Email (phishing), VoIP (vishing), web (watering hole/scareware).
Payloads: Credential theft, malware (e.g., trojans), or financial fraud.
Mitigation: User training, email filters (e.g., DMARC), endpoint protection.
Security Implications: Social engineering accounts for ~90% of breaches (e.g., Verizon DBIR 2023), as it exploits unpatchable human error. CNSP likely emphasizes awareness (e.g., phishing simulations) and layered defenses (e.g., MFA).
Why other options are incorrect:
A . Probes: Reconnaissance techniques (e.g., port scanning) to identify vulnerabilities, not manipulation-based like these attacks.
B . Insider threats: Malicious actions by authorized users (e.g., data theft by employees), not external human-targeting tactics.
D . Ransomware: A malware type (e.g., WannaCry) that encrypts data for ransom, not a manipulation method-though phishing often delivers it.
Real-World Context: The 2016 DNC hack used spear phishing to steal credentials, showing social engineering's potency.
NEW QUESTION # 38
What is the response from an open UDP port which is not behind a firewall?
- A. No response
- B. ICMP message showing Port Unreachable
- C. A SYN packet
- D. A FIN packet
Answer: A
Explanation:
UDP's connectionless nature means it lacks inherent acknowledgment mechanisms, affecting its port response behavior.
Why B is correct: An open UDP port does not respond unless an application explicitly sends a reply. Without a firewall or application response, the sender receives no feedback, per CNSP scanning guidelines.
Why other options are incorrect:
A: ICMP Port Unreachable indicates a closed port, not an open one.
C: SYN packets are TCP-specific, not UDP.
D: FIN packets are also TCP-specific.
NEW QUESTION # 39
Which of the following algorithms could be used to negotiate a shared encryption key?
- A. SHA1
- B. Diffie-Hellman
- C. Triple-DES
- D. AES
Answer: B
Explanation:
Negotiating a shared encryption key involves a process where two parties agree on a secret key over an insecure channel without directly transmitting it. This is distinct from encryption or hashing algorithms, which serve different purposes.
Why C is correct: The Diffie-Hellman (DH) algorithm is a key exchange protocol that enables two parties to establish a shared secret key using mathematical operations (e.g., modular exponentiation). It's widely used in protocols like TLS and IPsec, as noted in CNSP for secure key negotiation.
Why other options are incorrect:
A: Triple-DES is a symmetric encryption algorithm for data encryption, not key negotiation.
B: SHA1 is a hash function for integrity, not key exchange.
D: AES is a symmetric encryption algorithm, not a key exchange mechanism.
NEW QUESTION # 40
On a Microsoft Windows operating system, what does the following command do?
net localgroup Sales Sales_domain /add
- A. Add a domain group to the local group Sales
- B. Add a new user to the local group Sales
- C. Add a local group Sales to the domain group
- D. Display the list of the users of a local group Sales
Answer: A
Explanation:
The net localgroup command manages local group memberships on Windows systems, with syntax dictating its action.
Why B is correct: net localgroup Sales Sales_domain /add adds the domain group Sales_domain to the local group Sales, granting its members local group privileges. CNSP covers this for privilege escalation testing.
Why other options are incorrect:
A: Displaying users requires net localgroup Sales without /add.
C: Adding a user requires a username, not a group name like Sales_domain.
D: The reverse (local to domain) uses net group, not net localgroup.
NEW QUESTION # 41
What is the response from a closed TCP port which is not behind a firewall?
- A. A RST and an ACK packet
- B. A FIN and an ACK packet
- C. A SYN and an ACK packet
- D. ICMP message showing Port Unreachable
Answer: A
Explanation:
TCP uses a structured handshake, and its response to a connection attempt on a closed port follows a specific protocol when unobstructed by a firewall.
Why C is correct: A closed TCP port responds with a RST (Reset) and ACK (Acknowledgment) packet to terminate the connection attempt immediately. CNSP highlights this as a key scanning indicator.
Why other options are incorrect:
A: ICMP Port Unreachable is for UDP, not TCP.
B: FIN/ACK is for closing active connections, not rejecting new ones.
D: SYN/ACK indicates an open port during the TCP handshake.
NEW QUESTION # 42
Which Kerberos ticket is required to generate a Silver Ticket?
- A. Service Account Ticket
- B. Ticket-Granting Ticket
- C. There is no specific ticket required for generating a Silver Ticket
- D. Session Ticket
Answer: A
Explanation:
A Silver Ticket is a forged Kerberos Service Ticket (TGS - Ticket Granting Service) in Active Directory, granting access to a specific service (e.g., MSSQL, CIFS) without KDC interaction. Unlike a Golden Ticket (TGT forgery), it requires:
Service Account's NTLM Hash: The target service's account (e.g., MSSQLSvc) hash, not a ticket.
Forgery: Tools like Mimikatz craft the TGS (e.g., kerberos::golden /service:<spn> /user:<user> /ntlm:<hash>).
Kerberos Flow (RFC 4120):
TGT (Ticket-Granting Ticket): Obtained via AS (Authentication Service) with user creds.
TGS: Requested from TGS (Ticket Granting Service) using TGT for service access.
Silver Ticket Process:
No TGT needed; the attacker mimics the TGS step using the service account's stolen hash (e.g., from a compromised host).
C . Service Account Ticket: Misnomer-it's the hash of the service account (e.g., MSSQLSvc) that enables forgery, not a pre-existing ticket. CNSP's phrasing likely tests this nuance.
Security Implications: Silver Tickets are stealthier than Golden Tickets (service-specific, shorter-lived). CNSP likely stresses hash protection (e.g., LAPS) and Kerberos monitoring.
Why other options are incorrect:
A . Session Ticket: Not a Kerberos term; confuses session keys.
B . TGT: Used for Golden Tickets, not Silver.
D: Incorrect; the service account's hash (implied by "ticket") is essential.
Real-World Context: Silver Tickets exploited in APT29 attacks (2020 SolarWinds) for lateral movement.
NEW QUESTION # 43
The Active Directory database file stores the data and schema information for the Active Directory database on domain controllers in Microsoft Windows operating systems. Which of the following file is the Active Directory database file?
- A. NTDS.MDB
- B. MSAD.MDB
- C. NTDS.DIT
- D. NTDS.DAT
Answer: C
Explanation:
The Active Directory (AD) database on Windows domain controllers contains critical directory information, stored in a specific file format.
Why D is correct: The NTDS.DIT file (NT Directory Services Directory Information Tree) is the Active Directory database file, located in C:\Windows\NTDS\ on domain controllers. It stores all AD objects (users, groups, computers) and schema data in a hierarchical structure. CNSP identifies NTDS.DIT as the key file for AD data extraction in security audits.
Why other options are incorrect:
A . NTDS.DAT: Not a valid AD database file; may be a confusion with other system files.
B . NTDS.MDB: Refers to an older Microsoft Access database format, not used for AD.
C . MSAD.MDB: Not a recognized file for AD; likely a misnomer.
NEW QUESTION # 44
How many usable TCP/UDP ports are there?
- A. 0
- B. 1
- C. 2
- D. 3
Answer: C
Explanation:
TCP (Transmission Control Protocol) and UDP (User Datagram Protocol) port numbers are defined by a 16-bit field in their packet headers, as specified in RFC 793 (TCP) and RFC 768 (UDP). A 16-bit integer ranges from 0 to 65,535, yielding a total of 65,536 possible ports (2^16). However, port 0 is universally reserved across both protocols and is not considered "usable" for standard network communication. According to the Internet Assigned Numbers Authority (IANA), port 0 is designated for special purposes, such as indicating an invalid or dynamic port assignment in some systems (e.g., when a client requests an ephemeral port). In practice, operating systems and applications avoid binding to port 0 for listening services, and it's often used in error conditions or as a placeholder in protocol implementations (e.g., socket programming).
Thus, the usable port range spans from 1 to 65,535, totaling 65,535 ports. These ports are categorized by IANA into:
Well-Known Ports (0-1023): Reserved for system services (e.g., HTTP on 80/TCP). Note that 0 is still reserved within this range.
Registered Ports (1024-49151): Assigned to user applications.
Dynamic/Ephemeral Ports (49152-65535): Used temporarily by clients.
From a security perspective, understanding the usable port count is critical for firewall configuration, port scanning (e.g., with Nmap), and detecting anomalies (e.g., services binding to unexpected ports). Misconfiguring a system to use port 0 could lead to protocol errors or expose vulnerabilities, though it's rare. The CNSP curriculum likely emphasizes this distinction to ensure practitioners can accurately scope network security assessments.
Why other options are incorrect:
A . 65536: This reflects the total number of possible ports (0-65535), but it includes the reserved port 0, which isn't usable for typical TCP/UDP communication. In security contexts, including port 0 in a count could lead to misconfigured rules or scanning errors.
C . 63535: This is an arbitrary number with no basis in the 16-bit port structure. It might stem from a typo or misunderstanding (e.g., subtracting 2000 from 65535 incorrectly), but it's invalid.
D . 65335: Similarly, this lacks grounding in protocol standards. It could be a miscalculation (e.g., subtracting 200 from 65535), but it doesn't align with TCP/UDP specifications.
Real-World Context: In penetration testing, tools like Nmap scan ports 1-65535 by default, excluding 0 unless explicitly specified (e.g., -p0-65535), reinforcing that 65,535 is the practical usable count.
NEW QUESTION # 45
Which of the following protocols is not vulnerable to address spoofing attacks if implemented correctly?
- A. IP
- B. UDP
- C. TCP
- D. ARP
Answer: C
Explanation:
Address spoofing fakes a source address (e.g., IP, MAC) to impersonate or amplify attacks. Analyzing protocol resilience:
C . TCP (Transmission Control Protocol):
Mechanism: Three-way handshake (SYN, SYN-ACK, ACK) verifies both endpoints.
Client SYN (Seq=X), Server SYN-ACK (Seq=Y, Ack=X+1), Client ACK (Ack=Y+1).
Spoofing Resistance: Spoofer must predict the server's sequence number (randomized in modern stacks) and receive SYN-ACK, impractical without session hijacking or MITM.
Correct Implementation: RFC 793-compliant, with anti-spoofing (e.g., Linux tcp_syncookies).
A . UDP:
Connectionless (RFC 768), no handshake. Spoofed packets (e.g., source IP 1.2.3.4) are accepted if port is open, enabling reflection attacks (e.g., DNS amplification).
B . ARP (Address Resolution Protocol):
No authentication (RFC 826). Spoofed ARP replies (e.g., fake MAC for gateway IP) poison caches, enabling MITM (e.g., arpspoof).
D . IP:
No inherent validation at Layer 3 (RFC 791). Spoofed source IPs pass unless filtered (e.g., ingress filtering, RFC 2827).
Security Implications: TCP's handshake makes spoofing harder, though not impossible (e.g., blind spoofing with sequence prediction, mitigated since BSD 4.4). CNSP likely contrasts this with UDP/IP's vulnerabilities in DDoS contexts.
Why other options are incorrect:
A, B, D: Lack handshake or authentication, inherently spoofable.
Real-World Context: TCP spoofing was viable pre-1990s (e.g., Mitnick attack); modern randomization thwarts it.
NEW QUESTION # 46
What user account is required to create a Golden Ticket in Active Directory?
- A. Local User account
- B. Domain User account
- C. Service account
- D. KRBTGT account
Answer: D
Explanation:
A Golden Ticket is a forged Kerberos Ticket-Granting Ticket (TGT) in Active Directory (AD), granting an attacker unrestricted access to domain resources by impersonating any user (e.g., with Domain Admin privileges). Kerberos, per RFC 4120, relies on the KRBTGT account-a built-in service account on every domain controller-to encrypt and sign TGTs. To forge a Golden Ticket, an attacker needs:
The KRBTGT password hash (NTLM or Kerberos key), typically extracted from a domain controller's memory using tools like Mimikatz.
Additional domain details (e.g., SID, domain name).
Process:
Compromise a domain controller (e.g., via privilege escalation).
Extract the KRBTGT hash (e.g., lsadump::dcsync /user:krbtgt).
Forge a TGT with arbitrary privileges using the hash (e.g., Mimikatz's kerberos::golden command).
The KRBTGT account itself isn't "used" to create the ticket; its hash is the key ingredient. Unlike legitimate TGTs issued by the KDC, a Golden Ticket bypasses authentication checks, persisting until the KRBTGT password is reset (a rare event in most environments). CNSP likely highlights this as a high-severity AD attack vector.
Why other options are incorrect:
A . Local User account: Local accounts are machine-specific, lack domain privileges, and can't access the KRBTGT hash stored on domain controllers.
B . Domain User account: A standard user has no inherent access to domain controller credentials or the KRBTGT hash without escalation.
C . Service account: While service accounts may have elevated privileges, they don't automatically provide the KRBTGT hash unless compromised to domain admin level-still insufficient without targeting KRBTGT specifically.
Real-World Context: The 2014 Sony Pictures hack leveraged Golden Tickets, emphasizing the need for KRBTGT hash rotation post-breach (a complex remediation step).
NEW QUESTION # 47
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